hard algebra

Question

0

515

1

Solve

$9x^{2} + 12x + 4 = x^{3} + 3x^{2}\left(\sqrt[3]{25} - 1\right) + 3x \left(\sqrt[3]{25} - 1\right)^{2} + \left(\sqrt[3]{25} - 1\right)^{3}$

Guest Jul 21, 2020

Alan · Answer 1 · 2020-07-21T06:56:39

As follows:

(The other two solutions are ≈ -0.975 and 3.203)