Hard C&P porblem with restrictions

Question

0

951

4

+198

Let a and b be events.]

Max0815 Sep 3, 2018

edited by Max0815 Sep 5, 2018
edited by Max0815 Sep 5, 2018
edited by Max0815 Sep 15, 2018

+198

0

Thanks!!!

Max0815 Sep 5, 2018

Max0815 · Answer 1 · 2018-09-03T10:45:17

Someone please help!!!

Max0815 · Answer 2 · 2018-09-04T01:41:33

Somebody please help!

Guest · Answer 3 · 2018-09-04T06:13:27

it won't be true as long as $P(A) \neq P(B)$

$P(A \wedge B) = P(A|B)P(B) = P(B|A)P(A) \\ \\ \text{clearly } P(A) \neq P(B) \Rightarrow P(A|B) \neq P(B|A)$