+0  
 
0
932
4
avatar+198 

Let a and b be events.]

 Sep 3, 2018
edited by Max0815  Sep 5, 2018
edited by Max0815  Sep 5, 2018
edited by Max0815  Sep 15, 2018
 #1
avatar+198 
0

Someone please help!!!

 Sep 3, 2018
 #2
avatar+198 
0

Somebody please help!

 Sep 4, 2018
 #3
avatar
+3

it won't be true as long as \(P(A) \neq P(B)\)

 

\(P(A \wedge B) = P(A|B)P(B) = P(B|A)P(A) \\ \\ \text{clearly } P(A) \neq P(B) \Rightarrow P(A|B) \neq P(B|A)\)

 Sep 4, 2018
 #4
avatar+198 
0

Thanks!!!

 Sep 5, 2018

1 Online Users