Hard C&P porblem with restrictions

Someone please help!!!

Somebody please help!

it won't be true as long as $P(A) \neq P(B)$

$P(A \wedge B) = P(A|B)P(B) = P(B|A)P(A) \\ \\ \text{clearly } P(A) \neq P(B) \Rightarrow P(A|B) \neq P(B|A)$

Thanks!!!