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Given: SK = 52
SO ⊥ base
SO = 45
Find: R of the sphere

 

 Apr 26, 2020
 #1
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Call the center of the circle \(L\)

 

\(SL=r\)

\(KL=r\)

\(OL=45-r\)

 

By pythagorean theorem:

(Hypotenuse of Triangle SOK)^2 - (Longer side of triangle SOK)^2= (Hypotenuse of triangle KOL)^2 - (Shorter side of triangle KOL)^2

\(52^2-45^2=r^2-(45-r)^2\)

 

Now it's your turn to solve.

 Apr 27, 2020

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