hard question

4*7y+9+1=10

 

 10

-  1

-  9

--------

0

 

so then get 4*7y to 0 (so y = 0.....giving you 4*7y......4*(7*0).......4*(0)....0)

 

so y = 0

 

I could be wrong, but it may be right

$4\times7y+9+1=10$

 

$28y+9+1=10$

 

$28y+10=10$

 

$28y+10-10=10-10$

 

$28y+0=10-10$

 

$28y=10-10$

 

$28y=0$

 

$\frac{28y}{28}=\frac{0}{28}$

 

$\frac{1y}{1}=\frac{0}{28}$

 

$1y=\frac{0}{28}$

 

$y=\frac{0}{28}$

 

$y=0$

 

Now put the answer you came up with and put back into the original equation and solve to see if the answer you came up with is the correct answer.

 

$4\times7y+9+1=10$

 

$4\times7\times0+9+1=10$

 

$28\times0+9+1=10$

 

$0+9+1=10$

 

$9+1=10$

 

$10=10$

 

Because you came up with $10=10$, that means that $y=0$ is the correct answer.