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An icecupe has a mass of 384 gram, temp 0 degrees, and then energi melts the icecupe to water, how much energi?

 Nov 30, 2016

Best Answer 

 #1
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Latent heat of melting of ice = 334 J/g so energy required for 384 g is 384*334 J → 128.256 kJ

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 Nov 30, 2016
 #1
avatar+33653 
+10
Best Answer

Latent heat of melting of ice = 334 J/g so energy required for 384 g is 384*334 J → 128.256 kJ

.

Alan Nov 30, 2016

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