The roots of 7x^2 + x - 5 = 0 are a and b. Compute (a + 4) + (b + 4)
Re-write as \(a+b+8\)
By Vieta's, we know that \(a+b= -{b \over a} \). Plugging the values in, we find that \(a+b=-{1 \over 7}\)
We now have to add 8 to this total, and we find the final answer is \(\color{brown}\boxed{7 {6 \over 7}}\)