When the expression 4(x^2-2x+2)-7(x^3-3x+1) is fully simplified, what is the sum of the squares of the coefficients of the terms?
When we simplify it, it equals 4x^2-8x+8+-7x^3+21x-7 4^2=16 8^2=64 7^2=49
21^2=441 If we add them we get 570.