The polynomial \(x^{101} + Ax + B\) is divisible by \(x^2 + x + 1\) for some real numbers \(A\) and \(B\). Find \(A+B\)
+1252 https://web2.0calc.com/questions/sorry-for-re-posting-but-i-really-need-an-answer
+26393 The polynomial x^{101} + Ax + B is divisible by x^2 + x + 1 for some real numbers A and B.
Find A+B
answer see: https://web2.0calc.com/questions/sorry-for-re-posting-but-i-really-need-an-answer#r2
