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A math teacher wants to create a problem that involves multiplying a four-digit number by a
three-digit number. The four-digit number can only contain digits from 0 to 5, without repeats. The
three-digit number can only contains digits from 0 to 4, but repeats are allowed. How many such
problems are possible?

 Mar 20, 2021
 #1
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Possible  4 digit numbers =   5 * 5 * 4 * 3  =   300

 

Possible 3 digit numbers  =  4 * 5 * 5  =   100

 

Total problems = 300 * 100  =   30,000

 

cool cool cool

 Mar 20, 2021
 #2
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thank you!!

Guest Mar 20, 2021

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