For what value of k does the line represented by the equation −12−2kx=5y contain the point (14,−6)?
−12−2kx=5y
(14,−6)
So we can solve this for "k'
-1/2 - 2k(1/4) = 5(-6)
-1/2 - (1/2)k = - 30 multiply through by 2
-1 - k = -60
-k = - 59
k = 59
+612 
