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For what value of $k$ does the line represented by the equation $-\frac{1}{2}-2kx = 5y$ contain the point $\left(\frac{1}{4},-6\right)$?

gueesstt  May 4, 2018
 #1
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\(-\frac{1}{2}-2kx = 5y \)

 

\( \left(\frac{1}{4},-6\right)\)

 

 

So    we can solve this  for   "k'

 

-1/2  - 2k(1/4)  = 5(-6)

 

-1/2 - (1/2)k  = - 30         multiply through by 2

 

-1  - k  =  -60

 

-k =  - 59

 

k   = 59

 

 

cool cool cool

CPhill  May 4, 2018

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