Rhombus ABCD has perimeter 148, and one of its diagonals has length 28. what is the area of ABCD?
+36915 Rhombus sides are all equal 148 / 4 = 37 per side
the diagonals of a rhombus intersect at right angles (see image below) and bisect each other
using pythag theorem you can find 1/2 of the other diagonal to be sqrt 1173 for total digonal length 2 * sqrt 1173
Area of a rhombus = diagonal 1 * diagonal 2 / 2 = 28 * 2 sqrt1173 / 2 units2 <====== I trust you can finish
