+0  
 
0
89
1
avatar

Let a be the smallest integer satisfying the inequality x^2 - 15 < 12x, and let b be the largest integer satisfying the same inequality. What is b-a?

 Jan 16, 2022
 #1
avatar+13577 
0

 What is b-a?

 

Hello Guest!

 

x^2 - 15 < 12x

\( x^2-12x-15=0\\ x=6\pm\sqrt{36+15}\\ x_{max}=13.141...\\ x_{min}=-1.141...\)

a > \(x_{min}\)

a = - 1

b < \(x_{max}\)

b = 13

\({\color{blue}b-a}=13-(-1)\color{blue}=14\)

laugh  !

 Jan 16, 2022
edited by asinus  Jan 16, 2022
edited by asinus  Jan 16, 2022

13 Online Users

avatar
avatar