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Solve for \(x\)\(\frac{x}{7}+\frac{x}{3}=1-x\)

 Nov 29, 2020
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\(x=\frac{21}{31} \)

 

LCM or Least Common Multiplier of 3&7 = 21

\(\frac{x}{7}\cdot \:21+\frac{x}{3}\cdot \:21=1\cdot \:21-x\cdot \:21\)

 

Simplify:

\(3x+7x=21-21x \)

\(10x=21-21x\)

 

Add 21x to both sides:

\(10x+21x=21-21x+21x \)

\(31x=21\)

 

Divide:

\(\frac{31x}{31}=\frac{21}{31}\)

 

\(x=\frac{21}{31}\)

 

Hope it helps! :)

 Nov 29, 2020

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