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a student wrote the following equations:

                 3y + 6 = 2x

                 2y - 3x = 6

the lines represented by these equations are

 

a) parallel    b) the same line   c) perpendicular    d) intersecting,but not perpendicular

 Mar 22, 2015

Best Answer 

 #2
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3y + 6 = 2x    →  3y = 2x - 6  →  y = (2/3)x - 2

2y - 3x = 6    →   2y = 3x + 6 →  y = (3/2)x + 3

So...as Anonymous has said....the slopes are reciprocals, but not negative reciprocals...so this system has a single solution...... the lines intersect, but not at right angles. 

 

  

 Mar 22, 2015
 #1
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+5

D because when you put the eqation in y=mx+b form they have reciprical slope but they are not also opposite sign (-,+) so the anser is D

 Mar 22, 2015
 #2
avatar+130517 
+5
Best Answer

3y + 6 = 2x    →  3y = 2x - 6  →  y = (2/3)x - 2

2y - 3x = 6    →   2y = 3x + 6 →  y = (3/2)x + 3

So...as Anonymous has said....the slopes are reciprocals, but not negative reciprocals...so this system has a single solution...... the lines intersect, but not at right angles. 

 

  

CPhill Mar 22, 2015

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