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how do i solve 2xsquared plus 13x plus 7=0

 Mar 21, 2016
 #1
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Why don't write it like this:

2x^2 + 13x + 7 =0

 

Solve for x:
2 x^2+13 x+7 = 0

Divide both sides by 2:
x^2+(13 x)/2+7/2 = 0

Subtract 7/2 from both sides:
x^2+(13 x)/2 = -7/2

Add 169/16 to both sides:
x^2+(13 x)/2+169/16 = 113/16

Write the left hand side as a square:
(x+13/4)^2 = 113/16

Take the square root of both sides:
x+13/4 = sqrt(113)/4 or x+13/4 = -sqrt(113)/4

Subtract 13/4 from both sides:
x = sqrt(113)/4-13/4 or x+13/4 = -sqrt(113)/4

Subtract 13/4 from both sides:
Answer: |  x = sqrt(113)/4-13/4         or        x = -13/4-sqrt(113)/4

 Mar 21, 2016

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