0.2x + 0.3(x-27000)=800 Solve for x
\(\begin{array}{rcll} 0.2 \cdot x + 0.3\cdot (x-27000) &=& 800 \\ 0.2 \cdot x + 0.3\cdot x- 0.3\cdot 27000 &=& 800 \\ 0.5\cdot x- 0.3\cdot 27000 &=& 800 \\ 0.5\cdot x- 8100 &=& 800 \qquad & | \qquad + 8100 \\ 0.5\cdot x &=& 800 + 8100 \\ 0.5\cdot x &=& 8900 \\ 0.5\cdot x &=& 8900 \qquad & | \qquad \cdot 2 \\ x &=& 17800 \\ \end{array}\)