+0  
 
+10
684
1
avatar

shane swims 42 laps in 26 minutes and 19 seconds. how many minutes and seconds would it take shane to swim 15 laps at the same average speed

 Nov 6, 2015

Best Answer 

 #1
avatar+26400 
+25

shane swims 42 laps in 26 minutes and 19 seconds. how many minutes and seconds would it take shane to swim 15 laps at the same average speed

 

 

\(\begin{array}{rcll} 26\ {\text{minutes}} \text{ and } 19 \ {\text{seconds}} &=& 26\ {\text{minutes}} + \frac{19}{60}\ {\text{minutes}} \\ &=& \frac{ 26 \cdot 60 + 19 } {60 }\ {\text{minutes}} \\ &=& \frac{ 1579 } {60 }\ {\text{minutes}} \\ \end{array}\)

 

15 laps:

\(\begin{array}{rcll} t \cdot \frac{ 42\ \text{laps} } { \frac{ 1579 } {60 } \ {\text{minutes} } } &=& 15\ \text{laps} \\ t &=& \frac{ 15\ \text{laps} } { 42\ \text{laps} } \cdot \frac{ 1579 } {60 } \ {\text{minutes} } \\ t &=& \frac{ 1579 } {168 } \ {\text{minutes} } \\ t &=& 9\ {\text{minutes}} \text{ and } 24 \ {\text{seconds}} \\ \end{array}\)

 

laugh

 Nov 6, 2015
 #1
avatar+26400 
+25
Best Answer

shane swims 42 laps in 26 minutes and 19 seconds. how many minutes and seconds would it take shane to swim 15 laps at the same average speed

 

 

\(\begin{array}{rcll} 26\ {\text{minutes}} \text{ and } 19 \ {\text{seconds}} &=& 26\ {\text{minutes}} + \frac{19}{60}\ {\text{minutes}} \\ &=& \frac{ 26 \cdot 60 + 19 } {60 }\ {\text{minutes}} \\ &=& \frac{ 1579 } {60 }\ {\text{minutes}} \\ \end{array}\)

 

15 laps:

\(\begin{array}{rcll} t \cdot \frac{ 42\ \text{laps} } { \frac{ 1579 } {60 } \ {\text{minutes} } } &=& 15\ \text{laps} \\ t &=& \frac{ 15\ \text{laps} } { 42\ \text{laps} } \cdot \frac{ 1579 } {60 } \ {\text{minutes} } \\ t &=& \frac{ 1579 } {168 } \ {\text{minutes} } \\ t &=& 9\ {\text{minutes}} \text{ and } 24 \ {\text{seconds}} \\ \end{array}\)

 

laugh

heureka Nov 6, 2015

0 Online Users