Use the Law of Sines to find if 1 triangle, 2 triangles or no triangles exist if A = 62o, a = 10, and b = 7
+130536 sin(62) / 10 = sinB / 7
sinB = 10sin(62) / 7
sin-1 [7sin(62) /10 ] = B = about 38.17°
To see if we have another possible triangle, subtract 38.17 from 180 = about 141.83°
Note.......that when we add this to 62° we exceed 180°.....so.....only one triangle is possible
