Let n be a natural number with exactly 2 positive prime divisors. Of n^2 has 27 divisors, how many does n have?
Sorry, don't seem to understand your question!!
Here is n with exactly 2 prime divisors: n=5141 = 53 x 97. As you can see it has ONLY 2 prime divisors other than 1 and 5141 itself. If you square it, you always get 9 divisors:
5141^2 =26,429,881 =1 | 53 | 97 | 2809 | 5141 | 9409 | 272473 | 498677 | 26429881 (9 divisors)
So, I don't get how it could have 27 divisors !!!!
+26367 Let n be a natural number with exactly 2 positive prime divisors. Of n^2 has 27 divisors, how many does n have?
answer see: https://web2.0calc.com/questions/let-n-be-a-natural-number-with-exactly-2-positive_1
