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Let n be a natural number with exactly 2 positive prime divisors. Of n^2 has 27 divisors, how many does n have?

Guest Jun 23, 2018
 #1
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Sorry, don't seem to understand your question!!

 

Here is n with exactly 2 prime divisors: n=5141 = 53 x 97. As you can see it has ONLY 2 prime divisors other than 1 and 5141 itself. If you square it, you always get 9 divisors:

5141^2 =26,429,881 =1 | 53 | 97 | 2809 | 5141 | 9409 | 272473 | 498677 | 26429881 (9 divisors)

So, I don't get how it could have 27 divisors !!!!

Guest Jun 23, 2018
 #15
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Let n be a natural number with exactly 2 positive prime divisors. Of n^2 has 27 divisors, how many does n have?

 

answer see:  https://web2.0calc.com/questions/let-n-be-a-natural-number-with-exactly-2-positive_1

 

laugh

heureka  Jun 25, 2018

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