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# Help please I don't understand

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One number is four times another, and the sum of the two numbers is 155. What are the two numbers?

SmartMathMan  Nov 12, 2018
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We have 2 numbers $$x,y$$

$$x=4y$$ (1)

$$x+y=155$$<=> We are replacing the (1) => $$4y+y=155$$ <=> $$5y=155$$ <=> $$y=31$$

so we are replacing in the (1) $$x=4\times31$$<=> $$x=124$$

so the two numbers? is $$31$$ and $$124$$

Hope this helps!

Dimitristhym  Nov 12, 2018
edited by Dimitristhym  Nov 12, 2018
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thx dimitristhyn

SmartMathMan  Nov 12, 2018
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number 1 = x, number 2 = 155-x.

We have the equation $x = 4(155-x)$, which simplifies into $x = 620 - 4x$. Isolating x, we have $5x=620$, which simplifies into $x = 124$. The second number is $155-124$, which is $31$. Done, you are welcome.

Guest Nov 12, 2018
edited by Guest  Nov 12, 2018
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sorry im confused

SmartMathMan  Nov 12, 2018
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Sorry if you don't understand my solution sent me message to explain it step by step

Dimitristhym  Nov 12, 2018
edited by Dimitristhym  Nov 12, 2018
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Thanks for that solution,  Dimitristhym.......!!!!

CPhill  Nov 12, 2018
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Let the smaller number   = N

The greater number  = 4 times N   = 4N

And we know that

N + 4N   = 155

5N    = 155      divide both sides by 5

N =  31     [ the smaller number ]

And the larger number is  4 ( 31)  =  124

CPhill  Nov 12, 2018