One number is four times another, and the sum of the two numbers is 155. What are the two numbers?
We have 2 numbers \(x,y\)
\(x=4y \) (1)
\(x+y=155 \)<=> We are replacing the (1) => \(4y+y=155\) <=> \(5y=155\) <=> \(y=31\)
so we are replacing in the (1) \(x=4\times31\)<=> \(x=124\)
so the two numbers? is \(31\) and \(124\)
Hope this helps!
number 1 = x, number 2 = 155-x.
We have the equation $x = 4(155-x)$, which simplifies into $x = 620 - 4x$. Isolating x, we have $5x=620$, which simplifies into $x = 124$. The second number is $155-124$, which is $31$. Done, you are welcome.
sorry im confused