One number is four times another, and the sum of the two numbers is 155. What are the two numbers?

SmartMathMan Nov 12, 2018

#1**+1 **

We have 2 numbers \(x,y\)

\(x=4y \) (1)

\(x+y=155 \)<=> We are replacing the (1) => \(4y+y=155\) <=> \(5y=155\) <=> \(y=31\)

so we are replacing **in **the (1) \(x=4\times31\)<=> \(x=124\)

so the two numbers? is \(31\) and \(124\)

**Hope this helps!**

Dimitristhym Nov 12, 2018

#2**0 **

number 1 = x, number 2 = 155-x.

We have the equation $x = 4(155-x)$, which simplifies into $x = 620 - 4x$. Isolating x, we have $5x=620$, which simplifies into $x = 124$. The second number is $155-124$, which is $31$. Done, you are welcome.

Guest Nov 12, 2018

edited by
Guest
Nov 12, 2018

#3

#4**+1 **

Sorry if you don't understand my solution sent me message to explain it step by step

Dimitristhym
Nov 12, 2018