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Find the area of triangle JKL when LK is 20 units, angle L is 60 degrees, angle J 90 degrees

 Oct 5, 2020
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20 sin 60 = JK = 20 sqrt3/2

 

(20 sqrt 3 /2)^2   + JL^2 = 20^2

JL = 10

 

1/2 (10)(20 sqrt(3)/2)  = area in units2

 Oct 5, 2020

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