Find the area of triangle JKL when LK is 20 units, angle L is 60 degrees, angle J 90 degrees
20 sin 60 = JK = 20 sqrt3/2
(20 sqrt 3 /2)^2 + JL^2 = 20^2
JL = 10
1/2 (10)(20 sqrt(3)/2) = area in units2
