help please

Cos of what?

I'm gonna assume it is 40 with the tan

$tan{40}-9.8(\frac{20^2}{92*16^2*cos^2{40}*40})$

tan(40)-9.8(20^2/92*16^2*cos(40)*cos(40) *40) = -194075.942

-194075.942

I would have assummed they meant (cos(40))^2   read as cos squared 40 or cos 40 all squared

$tan 40-9.8*20^2/(92*16^2*(cos(40))^2)$

That would give 0.555471

But it is a guess at what the cos^2*40 meant