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A new alloy is made by mixing 72 grams of iron with 9 grams of zinc. How many grams of iron are required to make the alloy when combined with 144 grams of zinc?

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 Feb 4, 2020
 #1
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1152 grams of iron are required to make the alloy when combined with 144 grams of zinc

We will use the proportion to solve the problem

Let x2 be the quantity of iron when combined with 144 grams of zinc

So,

zinc in first alloy = z1 = 9 gm

Iron in first alloy = x1 = 72 gm

Zinc in second alloy = 144 gm

\(x_1:z_1::x_2:z_2\\72:9:: x_2 : 144\\\frac{72}{9} = \frac{x_2}{144}\\8 = \frac{x_2}{144}\\x_2 = 144*8\\x_2 = 1152\)

from Brainly.com credited to absor201. 

(Since I don't have much time so I copied it so yeah...)

 Feb 4, 2020
edited by tomsun  Feb 4, 2020
 #2
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[144 / 9]  x  72  = 1,152 grams of iron.

 Feb 4, 2020

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