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 Chris has a bag with 4 black socks and 6 red socks (so there are 10 socks in total). Timothy reaches into the bag and grabs two socks without replacement. Find the probability that he will not grab two red socks.

 Jun 13, 2020
 #1
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With 4 black socks and 6 red socks, he can end without two red socks in these ways:

 

1) grabbing two black socks:                             (4/10)·(3/9)  =  12/90

2) grabbing a red sock and then a black sock:  (6/10)·(4/9)  =   24/90

3) grabbing a black sock and then a red sock:  (4/10)·(6/9)  =  24/90

 

Since these are independent:  12/90 + 24/90 + 24/90  =  60/90  =  1/3

 

The probability that he will not have a pair of red socks:  1/3

 Jun 13, 2020
 #2
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Thank you!

can you please do the one with the square

Guest Jun 13, 2020
 #4
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not correct\

Guest Jun 14, 2020
 #3
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geno, its 2/3, 60/90 does not equal to 1/3. 2/3

 Jun 14, 2020
 #5
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I agree, its 2/3

 Jun 14, 2020

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