+0  
 
0
399
4
avatar+565 

\(P\)  is the midpoint of  \(\overline{BD}\)\(AP = BP = 4\)\(\overline{AP} \perp \overline{BD}\)\(\overline{BD} \perp \overline{DC}\) , \(\overline{AB} \perp \overline{BC}\)  . In simple radical form,

what is the perimeter of pentagon  \(ABCDP?\)

ant101  Jul 21, 2017

Best Answer 

 #1
avatar+27047 
+1

ABPA:  \(p_1=4+4+4\sqrt2 \)

 

BCDB: \(p_2=8+8+8\sqrt2 \)

 

BP:   \(p_3=4\)

 

ABCDPA: \(p=p_1+p_2-p_3\rightarrow20+12\sqrt2\)

Alan  Jul 21, 2017
edited by Alan  Jul 21, 2017
edited by Alan  Jul 21, 2017
 #1
avatar+27047 
+1
Best Answer

ABPA:  \(p_1=4+4+4\sqrt2 \)

 

BCDB: \(p_2=8+8+8\sqrt2 \)

 

BP:   \(p_3=4\)

 

ABCDPA: \(p=p_1+p_2-p_3\rightarrow20+12\sqrt2\)

Alan  Jul 21, 2017
edited by Alan  Jul 21, 2017
edited by Alan  Jul 21, 2017
 #3
avatar+565 
0

its wrong

ant101  Jul 28, 2017
 #4
avatar
0

That is right!!!!!!! . I gave the right answer, which is 16 + 12sqrt(2), but they wouldn't accept it!!!!!.

Guest Jul 28, 2017

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