P is the midpoint of ¯BD . AP=BP=4 , ¯AP⊥¯BD , ¯BD⊥¯DC , ¯AB⊥¯BC . In simple radical form,
what is the perimeter of pentagon ABCDP?
ABPA: p1=4+4+4√2
BCDB: p2=8+8+8√2
BP: p3=4
ABCDPA: p=p1+p2−p3→20+12√2
its wrong
That is right!!!!!!! . I gave the right answer, which is 16 + 12sqrt(2), but they wouldn't accept it!!!!!.