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There exist constants   and  such that
for all real numbers  Enter the ordered triple 
\(\[3x^2 + 12x + 4 = a(x - h)^2 + k\] \)

 Jul 13, 2020
edited by Guest  Jul 13, 2020
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Complete the square:

3x^2 + 12x + 4 = 3(x + 6)^2 - 104

 

==> a = 3, h = -6, k = -104 

 Jul 14, 2020

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