+6 Provability for a bomb found in a plane in 2010, 2011, 2012 was: 9*10-7
A person believed he had a trick for a safer flight without any bombs at all, so he carried a bomb with him on the plane.
The probability of two bombs on board has to be less than the probability of one bomb! He sets up a calculation and uses year 2010 as an example.
P(Two bombs in 2010) = P(bomb) * P(bomb) = 9*10-7 * 9*10-7 = 81*10-14 = 8,1 * 10-13
This person carries his bomb along and does not want to defuse it, only use it as a dummy bomb. That is because he thinks that the provability for two bombs in one bomb is less likely.
Sadly he is arrested and jailed. Why did his theory fail?
+118723 In his case the probability of at least 1 bomb was 100% or 1 because he took it on board with him.
So the probability of two bombs, just in his case was 1* 9*10-7 =9*10-7
Taking the extra bomb on board did not decrease his chances of another being on the plane.
It just got him arrested 
(I think that is what you meant?)
+118723 In his case the probability of at least 1 bomb was 100% or 1 because he took it on board with him.
So the probability of two bombs, just in his case was 1* 9*10-7 =9*10-7
Taking the extra bomb on board did not decrease his chances of another being on the plane.
It just got him arrested
(I think that is what you meant?)
