f(x) = -2x + m, f(-3) = 3f(0)
I'm having trouble figuring out the second part. f(-3) = 3f(0) <- how do you calculate that number?
f(x) = -2x + m
f(-3) = -2(-3) + m = 6 + m
f(0) = -2(0) + m = m
Since f(-3) = 3·f(0) Substitute the values found above to get:
---> 6 + m = 3[m]
6 + m = 3m
6 = 2m
m = 3
