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am I correct?

 

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The graph shows the linear relation between log25y and log5x.Ify=kxn, then k=??

 

 Feb 15, 2015

Best Answer 

 #1
avatar+33616 
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1. Yes, you are correct.

 

2. When log5x = 0 then log25y = 2

This means that when x = 50 then y = 252  or when x = 1 then y =625

If, in general, y = k*xn then we must have 625 = k*1n or just k = 625

.

 Feb 15, 2015
 #1
avatar+33616 
+5
Best Answer

1. Yes, you are correct.

 

2. When log5x = 0 then log25y = 2

This means that when x = 50 then y = 252  or when x = 1 then y =625

If, in general, y = k*xn then we must have 625 = k*1n or just k = 625

.

Alan Feb 15, 2015

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