For what value of p does x2 + 2x + p = 0 have real roots?
If p = 1, then x2 + 2x + p = 0 ---> x2 + 2x + 1 = 0 ---> (x + 1)2 = 0 has a double root with x = -1.
If p < 1, then x2 + 2x + p = 0 will have two real roots.
Ip p > 1, then there will be no real roots.
