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Solve the equation:

(25x+4)^2+3=0

 Jun 17, 2016
edited by Guest  Jun 17, 2016
 #1
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((-100)±(193.64i))/(1250)

 Jun 17, 2016
edited by Guest  Jun 17, 2016
 #3
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"Solve the equation:

(25x+4)^2+3=0"

 

(25x + 4)2 = -3

 

25x + 4 = +/-sqrt(-3)    or   25x + 4 = +/-sqrt(3)i

 

25x = -4 +/-sqrt(3)i

 

x = -4/25 +/-sqrt(3)i/25  (or x = -0.16 +/- 0.069i)

.

 Jun 17, 2016

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