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help with sum

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507

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Compute $\displaystyle \sum_{k = 1}^{99} \frac{k}{1 + k^2 + k^4}$

Guest Jul 23, 2020

2⁺⁰ Answers

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sumfor(k, 1, 99, k / (1 + k^2 + k^4)) = 4950 / 9901

Guest Jul 23, 2020

+33654

+1

As follows:

Alan Jul 23, 2020

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