+0  
 
0
112
2
avatar

Compute \(\displaystyle \sum_{k = 1}^{99} \frac{k}{1 + k^2 + k^4}\)

 Jul 23, 2020
 #1
avatar
0

sumfor(k, 1, 99, k / (1 + k^2 + k^4)) = 4950 / 9901

 Jul 23, 2020
 #2
avatar+31506 
+1

As follows:

 

 Jul 23, 2020

23 Online Users