Find the sum of the first six terms in the geometric sequence 12,14,18,…. Express your answer as a common fraction.
S = (1/2) ( 1 - (1/2)^6 ) / ( 1 - 1/2) = 63/64 ( we could see this from the other problem )
This 6-term geometric series has first term a0=12 and ratio 1/2, so it has value
12(1−(12)6)1−12=1−(12)6=1−164=6364.