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Find all real numbers x and y such that 2x^2 + y^2 - 2xy + 12y + 72 <= 0.

 Dec 3, 2019
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x^2-2xy+y^2+x^2+12y+72 <= 0

(x-y)^2+x^2+12y+72 <= 0

(x-y)^2 has to be greater than or equal to 0.

x^2 has to be greater than or equal to 0.

So 12y+72 has to be less than or equal to 0.

Based on this, can you find it?

 

You are very welcome!

:P

 Dec 3, 2019

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