Help.

For inscribed quadrilaterals, opposite angles are supplementary. 
By setting the measures of B plus D equal to 180, we solve for x.
$x+24+x+10=180\\ x=73$ 
You use this x value to plug into x+15 (measure of angle A).
Opposite angles are supplementary so you subtract the measure of angle A you just calculated from 180 to get the measure of angle C. 

$x+15\\ 73+15=88\\ 180-88=92$

90 degrees?