Is sin= 1/sec(90-theta) true or false why or why not. I got true but dont known how with out using a caculator
sin(theta) = cos(90° - theta) = 1/sec(90° - theta)
Note that cos(90° - theta) = cos(90°)cos(theta) + sin(90°)sin(theta) = 0*cos(theta) + 1*sin(theta) = sin(theta)
