3y+53=7y-55 add 55 to BOTH sides and subtract 3y from BOTH sides to get:
108 = 4y divide both sides by 4 to get
27 = y
+1904 \(3y+53=7y-55\)
\(3y=7y-108\)
\(-4y=-108\)
\(y=27\)
Replace \(y\) with 27 in the original problem to check if the answer is correct.
\(3\times27+53=7\times27-55\)
\(81+53=7\times27-55\)
\(134=7\times27-55\)
\(134=189-55\)
\(134=134\)
That checks out. The answer of \(y=27\) is correct.
