In the five-digit number 3A25B, the digits A and B are chosen at random 0 to 9. What is the probability that the resulting number is divisible by 99?
There are 90,000 integers between 10,000 and 99,999. Of those 90,000 exactly 909 are divisible by 99.
Therefore, the probability is: 909 / 90,000 =0.0101 = 1.01 %
