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In the five-digit number 3A25B, the digits A and B are chosen at random 0 to 9.  What is the probability that the resulting number is divisible by 99?

 Jun 20, 2020
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There are 90,000 integers between 10,000 and 99,999. Of those 90,000 exactly 909 are divisible by 99.

 

Therefore, the probability is: 909 / 90,000 =0.0101 = 1.01 %

 Jun 20, 2020
edited by Guest  Jun 20, 2020

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