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In the five-digit number 3A25B, the digits A and B are chosen at random 0 to 9. What is the probability that the resulting number is divisible by 99?

Guest Jun 20, 2020

Guest · Answer 1 · 2020-06-20T08:00:02

There are 90,000 integers between 10,000 and 99,999. Of those 90,000 exactly 909 are divisible by 99.

Therefore, the probability is: 909 / 90,000 =0.0101 = 1.01 %