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The expression $\dfrac{\sqrt[4]{7}}{\sqrt[3]{7}}$ equals $7$ raised to what power?

 Dec 21, 2022
 #1
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The answer is 7/12.

 Dec 21, 2022
 #2
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 \(\dfrac{\sqrt[4]{7}}{\sqrt[3]{7}} = 7 \)

\({\sqrt[4]{7} \over \sqrt[3]{7}} = {7^{1 \over 4} \over 7^{1 \over 3}} = 7^{-1 \over 12}\)

\(\color{brown}\boxed{-{1 \over 12}} \)

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 Dec 21, 2022

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