The expression $\dfrac{\sqrt[4]{7}}{\sqrt[3]{7}}$ equals $7$ raised to what power?
+2668 \(\dfrac{\sqrt[4]{7}}{\sqrt[3]{7}} = 7 \)
\({\sqrt[4]{7} \over \sqrt[3]{7}} = {7^{1 \over 4} \over 7^{1 \over 3}} = 7^{-1 \over 12}\)
\(\color{brown}\boxed{-{1 \over 12}} \)
.
