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Let \(\mathbf{v} = (1,0,1),\) and let \(\mathbf{p}\) be the projection of \(\mathbf{v}\) onto the plane 2x + 3y + z = 0. What is \(\mathbf{v} - \mathbf{p}?\)

 Jun 19, 2020
 #1
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v - p = (2,-7,1).

 Jun 20, 2020

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