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# help

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48
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+418

In how many ways can the digits of  be arranged to form a 5-digit number? (Remember, numbers cannot begin with 0.)

Logic  Oct 18, 2018
#1
+307
0

Its 5! = 1*2*3*4*5 = 120 different numbers with 5-digit numbers!

Dimitristhym  Oct 18, 2018
#2
+2729
+2

If you are strictly enforcing 5 digits, as in no number can start with any number of zeros.

Then we have

$$n = 9 \cdot 10^4 = 90000$$

Rom  Oct 18, 2018
#3
+307
+1

He means with all numbers i understand with 5 numbers all the posible numbers we can take.I'm sorry ! :(

Dimitristhym  Oct 18, 2018