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In how many ways can the digits of be arranged to form a 5-digit number? (Remember, numbers cannot begin with 0.)

Logic Oct 18, 2018

Dimitristhym · Answer 1 · 2018-10-18T01:25:00

Its 5! = 1*2*3*4*5 = 120 different numbers with 5-digit numbers!

Rom · Answer 2 · 2018-10-18T01:50:24

If you are strictly enforcing 5 digits, as in no number can start with any number of zeros.

Then we have

\(n = 9 \cdot 10^4 = 90000\)