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If

\(f(x) = \begin{cases} 2x-5 &\quad \text{if } x \ge 3, \\ -x + 5 &\quad \text{if } x < 3, \end{cases} \)

then for how many values of \(x\) is \(f(f(x))=3\)?

 Jun 27, 2020
edited by Guest  Jun 27, 2020
edited by Guest  Jun 27, 2020
 #1
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f(f(x)) = 3 for five vaues of x.

 Jun 30, 2020

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