If
\(f(x) = \begin{cases} 2x-5 &\quad \text{if } x \ge 3, \\ -x + 5 &\quad \text{if } x < 3, \end{cases} \)
then for how many values of \(x\) is \(f(f(x))=3\)?
f(f(x)) = 3 for five vaues of x.
