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Solve \(\log _{ 3x+5 }{ \big(9{ x }^{ 2 }+8x+8\big) } >2 \)

I have no idea how to do this.

Guest Jul 4, 2020

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1⁺⁰ Answers

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Since log_b(a) = x ---> b^x = a

log_{3x + 5}(9x² + 8x + 8) > 2 ----> (3x + 5)² < 9x² + 8x + 8

Then continue ...

geno3141 Jul 4, 2020

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