help

Test the quadratic equation:

 \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

a=1

b=-6

c=2

solve the quadratic equation and see if they're real or not :) the roots aren't real if they include the square root of a negative nuumber.

Use the quadratic formula to find the roots

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)       a = 1   b = -6   c = 2    

 

x = 3 +- sqrt 7          real