+0

# help

0
93
2

Are the roots of x^2 - 6x + 2 = 0 real or not?

Dec 24, 2019

#1
+245
+2

Test the quadratic equation:

$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$$

a=1

b=-6

c=2

solve the quadratic equation and see if they're real or not :) the roots aren't real if they include the square root of a negative nuumber.

Dec 24, 2019
#2
+21980
+1

Use the quadratic formula to find the roots

$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$$       a = 1   b = -6   c = 2

x = 3 +- sqrt 7          real

Dec 24, 2019