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Are the roots of x^2 - 6x + 2 = 0 real or not?

 Dec 24, 2019
 #1
avatar+245 
+2

Test the quadratic equation:

 \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

a=1

b=-6

c=2

solve the quadratic equation and see if they're real or not :) the roots aren't real if they include the square root of a negative nuumber.

 Dec 24, 2019
 #2
avatar+21980 
+1

Use the quadratic formula to find the roots

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)       a = 1   b = -6   c = 2    

 

x = 3 +- sqrt 7          real 

 Dec 24, 2019

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