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The number 111...1 has 102 ones, and the number 222...2 has 101 twos. Suppose you do the
subtraction 111...1 − 222...2 to get a whole number. What is the sum of the digits of this whole number?

 Jun 27, 2020
 #1
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[111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111] - [22222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222] =8 8888888888 8888888888 8888888888 8888888888 8888888888 8888888888 8888888888 8888888888 8888888888 8888888889 = 809 sum  total.

 Jun 27, 2020

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