In the xy-plane, the graph y=3x^2-14x intersects the graph of x=y at the points (0,0) and (a,a). What is the value of a?
Let's find where y = 3x2 - 14x and x = y intersect by replace the y-term in the first equation with x:
x = 3x2 - 14x ---> 0 = 3x2 - 15x ---> 0 = 3x(x - 5) ---> x = 0 or x = 5
The value of a is 5.
