Given that a particular positive integer is a four-digit palindrome, what is the probability that it is a multiple of 99?Express your answer as a common fraction.
There are the following palindromes which are multiple of 99: 1881, 2772, 3663, 4554, 5445, 6336, 7227, 8118, 9009, 9999 = Total of 10 9999 - 1,000 + 1 =9,000 4-digit numbers 10/9,000 =1 / 900 - probability of multiples of 99
