\(\frac{2}{3}s + \frac{1}{3}=\frac{3}{4}s-\frac{1}{4}\)I totally forget how to add and subtract fractions
2/3 (s) + 1/3 = 3/4(s) - 1/4
multiply through by the common denominator of 3,4 = 12
8s + 4 = 9s - 3 add 3 to both sides, subtract 8s from both sides
7 = s
Thanks.