What is an equation in point-slope form for the line perpendicular to y=3x-10 that contains (-9,-1)
Perpendicular to y=3x-10 that contains (-9,-1)
Perpendicular lines have negative reciprocal slopes....so the slope of our line = - 1 /3
So we have
(y - - 1) = - [1 /3] ( x - - 9)
y + 1 = - [1 /3] ( x + 9) → point-slope form
+31 
