Help. ​

If we let x = 0, then y =  2(0)^2  = 0...so  (0,0)  will be on the graph

This eliminates the middle two graphs

If we let x  = 1, then y =  2(1)^2  =  2

So...( 1 , 2)   is on the graph

So...the first graph is correct.....